What is 3(x+1)^{(2)}+3(y-1)^{(2)}=6 ?

The solution to 3(x+1)^{(2)}+3(y-1)^{(2)}=6 is Circle with (a,b)=(-1,1),r=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3(x+1)^{(2)}+3(y-1)^{(2)}=6

3 (x + 1)^{(2)} + 3 (y - 1)^{(2)} = 6

(a, b) = (- 1, 1), r = 2

Solution steps

3 (x + 1)^{2} + 3 (y - 1)^{2} = 6

Rewrite

3 (x + 1)^{2} + 3 (y - 1)^{2} = 6

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 2

x^{2} + y^{2} - 8 x + 10 y + 8 = 0

3 x^{2} + 3 y^{2} - 3 y + 6 x - 4 = 0

(x + 2)^{2} + (y + 4)^{2} = 2

x^{2} + y^{2} - 2 x \leq 8

(x + 2)^{2} + (y + 4)^{2} = 9

What is 3(x+1)^{(2)}+3(y-1)^{(2)}=6 ?
The solution to 3(x+1)^{(2)}+3(y-1)^{(2)}=6 is Circle with (a,b)=(-1,1),r=sqrt(2)