What is (x-1)^{(2)}+(y-5)^{(2)}=16 ?

The solution to (x-1)^{(2)}+(y-5)^{(2)}=16 is Circle with (a,b)=(1,5),r=4

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(x-1)^{(2)}+(y-5)^{(2)}=16

(x - 1)^{(2)} + (y - 5)^{(2)} = 16

(a, b) = (1, 5), r = 4

Solution steps

(x - 1)^{2} + (y - 5)^{2} = 16

Rewrite

(x - 1)^{2} + (y - 5)^{2} = 16

in the form of the standard circle equation

(x - 1)^{2} + (y - 5)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, 5), r = 4

4 y^{2} + 4 x^{2} - 24 x + 32 y = - 84

x^{2} + y^{2} + 14 x - 7 y + 40 = 0

9 x^{2} + 36 x + 9 y^{2} + 72 y = - 155

(y + 4)^{2} + (x - 3)^{2} = 25

9 - 2 x^{2} - 2 y^{2} = 0

What is (x-1)^{(2)}+(y-5)^{(2)}=16 ?
The solution to (x-1)^{(2)}+(y-5)^{(2)}=16 is Circle with (a,b)=(1,5),r=4