What is 5-x^2-2x-y^2=0 ?

The solution to 5-x^2-2x-y^2=0 is Circle with (a,b)=(-1,0),r=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5-x^2-2x-y^2=0

5 - x^{2} - 2 x - y^{2} = 0

(a, b) = (- 1, 0), r = 6

Solution steps

5 - x^{2} - 2 x - y^{2} = 0

Rewrite

5 - x^{2} - 2 x - y^{2} = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 6

2 x^{2} + 2 y^{2} - 8 x + 12 y - 8 = 0

(x + 1)^{2} + (y + 6)^{2} = 100

(x - 1)^{2} + (y + 2)^{2} = 1

x^{(2)} + y^{(2)} - 6 x + 4 y - 12 = 0

x^{2} + y^{2} + 12 x - 4 y + 31 = 0

What is 5-x^2-2x-y^2=0 ?
The solution to 5-x^2-2x-y^2=0 is Circle with (a,b)=(-1,0),r=sqrt(6)