What is 5x^{(2)}+5y^{(2)}+10x+2y+3=0 ?

The solution to 5x^{(2)}+5y^{(2)}+10x+2y+3=0 is Circle with (a,b)=(-1,-1/5),r=(sqrt(11))/5

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5x^{(2)}+5y^{(2)}+10x+2y+3=0

5 x^{(2)} + 5 y^{(2)} + 10 x + 2 y + 3 = 0

(a, b) = (- 1, - \frac{1}{5}), r = \frac{11}{5}

Solution steps

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

Rewrite

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- \frac{1}{5}))^{2} = (\frac{11}{5})^{2}

Therefore the circle properties are:

(a, b) = (- 1, - \frac{1}{5}), r = \frac{11}{5}

x^{2} + y^{2} = 16 x

(x + 8)^{2} + (y + 3)^{2} = 4

x^{2} + y^{2} - 8 x + 12 y + 42 = 0

x^{2} + y^{2} - 10 x + 2 y + 18 = 0

(x - 5)^{2} + (y - 7)^{2} = 8

What is 5x^{(2)}+5y^{(2)}+10x+2y+3=0 ?
The solution to 5x^{(2)}+5y^{(2)}+10x+2y+3=0 is Circle with (a,b)=(-1,-1/5),r=(sqrt(11))/5