What is x^2+y^2-6x+2y=0 ?

The solution to x^2+y^2-6x+2y=0 is Circle with (a,b)=(3,-1),r=sqrt(10)

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x^2+y^2-6x+2y=0

x^{2} + y^{2} - 6 x + 2 y = 0

(a, b) = (3, - 1), r = 10

Solution steps

x^{2} + y^{2} - 6 x + 2 y = 0

Rewrite

x^{2} + y^{2} - 6 x + 2 y = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 1))^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (3, - 1), r = 10

x^{2} - 6 x + y^{2} + 8 y + 5 = 0

(x - (- 5))^{2} + (y - 0)^{2} = 4^{2}

(x + 1)^{2} + (y - 4)^{2} = 4

(x + \frac{19}{2})^{2} + (y - 230)^{2} = 9

(x + 1)^{2} + (y + 4)^{2} = 16

What is x^2+y^2-6x+2y=0 ?
The solution to x^2+y^2-6x+2y=0 is Circle with (a,b)=(3,-1),r=sqrt(10)