What is (x-5)^2+y^2=12 ?

The solution to (x-5)^2+y^2=12 is Circle with (a,b)=(5,0),r=sqrt(12)

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(x-5)^2+y^2=12

(x - 5)^{2} + y^{2} = 12

(a, b) = (5, 0), r = 12

Solution steps

(x - 5)^{2} + y^{2} = 12

Rewrite

(x - 5)^{2} + y^{2} = 12

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = (12)^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 12

x^{(2)} + y^{(2)} = 1

x^{2} + 6 x + y^{2} - 6 y = - 9

(x + i y - 1) ((x - i y) - 1) = 4 (x + i y + 1) (x - i y + 1)

(x + 3)^{2} + (y - 5)^{2} = 81

(2 x^{2} + 8 x) + (2 y^{2}) + 7 = 0

What is (x-5)^2+y^2=12 ?
The solution to (x-5)^2+y^2=12 is Circle with (a,b)=(5,0),r=sqrt(12)