What is (x+6)^2+(y-2)^2=4 ?

The solution to (x+6)^2+(y-2)^2=4 is Circle with (a,b)=(-6,2),r=2

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(x+6)^2+(y-2)^2=4

(x + 6)^{2} + (y - 2)^{2} = 4

(a, b) = (- 6, 2), r = 2

Solution steps

(x + 6)^{2} + (y - 2)^{2} = 4

Rewrite

(x + 6)^{2} + (y - 2)^{2} = 4

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 6, 2), r = 2

(x - 5)^{2} + (y - 1)^{2} = 49

(x - 1)^{2} + (y + 5)^{2} = 25

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

x^{2} + 8 x + y^{2} + 2 y + 13 = 0

x^{2} + y^{2} - 6 x + 4 y - 2 = 0

What is (x+6)^2+(y-2)^2=4 ?
The solution to (x+6)^2+(y-2)^2=4 is Circle with (a,b)=(-6,2),r=2