What is x^2+y^2-6x+12y+20=0 ?

The solution to x^2+y^2-6x+12y+20=0 is Circle with (a,b)=(3,-6),r=5

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x^2+y^2-6x+12y+20=0

x^{2} + y^{2} - 6 x + 12 y + 20 = 0

(a, b) = (3, - 6), r = 5

Solution steps

x^{2} + y^{2} - 6 x + 12 y + 20 = 0

Rewrite

x^{2} + y^{2} - 6 x + 12 y + 20 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 6))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 6), r = 5

x^{2} + 8 x + y^{2} - 2 y + 17 = 4 x^{2} - 24 x + 4 y^{2} - 16 y + 52

(x - 6)^{2} + (y - 3)^{2} = 324

(x + 2)^{2} + (y - \frac{3}{7})^{2} = \frac{16}{9}

x^{2} + y^{2} + 10 y + \frac{99}{4} = 0

(X + 3)^{2} + (Y - 0)^{2} = 9^{2}

What is x^2+y^2-6x+12y+20=0 ?
The solution to x^2+y^2-6x+12y+20=0 is Circle with (a,b)=(3,-6),r=5