What is x^{(2)}-5x+y^{(2)}+4y=46 ?

The solution to x^{(2)}-5x+y^{(2)}+4y=46 is Circle with (a,b)=(5/2 ,-2),r= 15/2

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x^{(2)}-5x+y^{(2)}+4y=46

x^{(2)} - 5 x + y^{(2)} + 4 y = 46

(a, b) = (\frac{5}{2}, - 2), r = \frac{15}{2}

Solution steps

x^{2} - 5 x + y^{2} + 4 y = 46

Rewrite

x^{2} - 5 x + y^{2} + 4 y = 46

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- 2))^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - 2), r = \frac{15}{2}

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3 x^{2} - 9 x + 3 y^{2} + 3 y = \frac{39}{2}

x^{2} + y^{2} + x - 2 y = 16

x^{2} + y^{2} + 4 x - 8 y + 11 = 0

(x - 6)^{2} + (y - 0)^{2} = 3^{2}

What is x^{(2)}-5x+y^{(2)}+4y=46 ?
The solution to x^{(2)}-5x+y^{(2)}+4y=46 is Circle with (a,b)=(5/2 ,-2),r= 15/2