What is (x+1/7)^2+(y-3/5)^2= 25/9 ?

The solution to (x+1/7)^2+(y-3/5)^2= 25/9 is Circle with (a,b)=(-1/7 , 3/5),r= 5/3

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(x+1/7)^2+(y-3/5)^2= 25/9

(x + \frac{1}{7})^{2} + (y - \frac{3}{5})^{2} = \frac{25}{9}

(a, b) = (- \frac{1}{7}, \frac{3}{5}), r = \frac{5}{3}

Solution steps

(x + \frac{1}{7})^{2} + (y - \frac{3}{5})^{2} = \frac{25}{9}

Rewrite

(x + \frac{1}{7})^{2} + (y - \frac{3}{5})^{2} = \frac{25}{9}

in the form of the standard circle equation

(x - (- \frac{1}{7}))^{2} + (y - \frac{3}{5})^{2} = (\frac{5}{3})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{7}, \frac{3}{5}), r = \frac{5}{3}

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What is (x+1/7)^2+(y-3/5)^2= 25/9 ?
The solution to (x+1/7)^2+(y-3/5)^2= 25/9 is Circle with (a,b)=(-1/7 , 3/5),r= 5/3