What is (x-1)^2=27-(y+1)^2 ?

The solution to (x-1)^2=27-(y+1)^2 is Circle with (a,b)=(1,-1),r=sqrt(27)

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(x-1)^2=27-(y+1)^2

(x - 1)^{2} = 27 - (y + 1)^{2}

(a, b) = (1, - 1), r = 27

Solution steps

(x - 1)^{2} = 27 - (y + 1)^{2}

Rewrite

(x - 1)^{2} = 27 - (y + 1)^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 1))^{2} = (27)^{2}

Therefore the circle properties are:

(a, b) = (1, - 1), r = 27

(x - 5)^{2} + (y - 6)^{2} = 20

x^{2} - 6 x + y^{2} + 10 y + 9 = 0

x^{2} + y^{2} + 12 x - 8 y + 16 = 0

(x - 4)^{2} + (y - 20)^{2} = 592^{2}

x^{2} + x + y^{2} + \frac{8}{3} y - \frac{1223}{36} = 0

What is (x-1)^2=27-(y+1)^2 ?
The solution to (x-1)^2=27-(y+1)^2 is Circle with (a,b)=(1,-1),r=sqrt(27)