What is 16x^2+96x+16y^2-40y-315+315=0+315 ?

The solution to 16x^2+96x+16y^2-40y-315+315=0+315 is Circle with (a,b)=(-3, 5/4),r= 11/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16x^2+96x+16y^2-40y-315+315=0+315

16 x^{2} + 96 x + 16 y^{2} - 40 y - 315 + 315 = 0 + 315

(a, b) = (- 3, \frac{5}{4}), r = \frac{11}{2}

Solution steps

16 x^{2} + 96 x + 16 y^{2} - 40 y - 315 + 315 = 0 + 315

Rewrite

16 x^{2} + 96 x + 16 y^{2} - 40 y - 315 + 315 = 0 + 315

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{5}{4})^{2} = (\frac{11}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{5}{4}), r = \frac{11}{2}

x^{2} - x - 6 + y^{2} = 0

x^{2} + (y - 5)^{2} = 100

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 4 ) ^{2}}{9} = 1

x^{2} - 10 x + y^{2} + 7 y + 12 = 0

2 x^{2} + 2 y^{2} + 13 x - 9 y - 20 = 0

What is 16x^2+96x+16y^2-40y-315+315=0+315 ?
The solution to 16x^2+96x+16y^2-40y-315+315=0+315 is Circle with (a,b)=(-3, 5/4),r= 11/2