What is 2x^2+2y^2+12y+10=0 ?

The solution to 2x^2+2y^2+12y+10=0 is Circle with (a,b)=(0,-3),r=2

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2x^2+2y^2+12y+10=0

2 x^{2} + 2 y^{2} + 12 y + 10 = 0

(a, b) = (0, - 3), r = 2

Solution steps

2 x^{2} + 2 y^{2} + 12 y + 10 = 0

Rewrite

2 x^{2} + 2 y^{2} + 12 y + 10 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 3))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, - 3), r = 2

(x - 7)^{(2)} + (y + 15)^{(2)} = 200

x^{2} + (y - 3)^{2} = 2.6

16 x^{2} + 96 x + 16 y^{2} - 14 y = 315

3 x^{2} + 3 y^{2} - 18 x - 30 y - 6 = 0

x^{2} + y^{2} - 22 x + 26 y + 254 = 0

What is 2x^2+2y^2+12y+10=0 ?
The solution to 2x^2+2y^2+12y+10=0 is Circle with (a,b)=(0,-3),r=2