What is (x-(-2))^2+(y-5)^2=4^2 ?

The solution to (x-(-2))^2+(y-5)^2=4^2 is Circle with (a,b)=(-2,5),r=4

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(x-(-2))^2+(y-5)^2=4^2

(x - (- 2))^{2} + (y - 5)^{2} = 4^{2}

(a, b) = (- 2, 5), r = 4

Solution steps

(x - (- 2))^{2} + (y - 5)^{2} = 4^{2}

Rewrite

(x - (- 2))^{2} + (y - 5)^{2} = 4^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 5)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 2, 5), r = 4

x^{2} - 3 x + y^{2} + 2 y - 14 = 0

x^{2} + y^{2} + 14 x - 8 y + 56 = 0

(x - 5)^{2} + (y + 2)^{2} = 49

x^{2} + y^{2} = 625

(x + 3) (x + 4) + (y - 4) (y - 3) = 0

What is (x-(-2))^2+(y-5)^2=4^2 ?
The solution to (x-(-2))^2+(y-5)^2=4^2 is Circle with (a,b)=(-2,5),r=4