What is 2x^2+2y^2+6x+10y+9=0 ?

The solution to 2x^2+2y^2+6x+10y+9=0 is Circle with (a,b)=(-3/2 ,-5/2),r=2

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2x^2+2y^2+6x+10y+9=0

2 x^{2} + 2 y^{2} + 6 x + 10 y + 9 = 0

(a, b) = (- \frac{3}{2}, - \frac{5}{2}), r = 2

Solution steps

2 x^{2} + 2 y^{2} + 6 x + 10 y + 9 = 0

Rewrite

2 x^{2} + 2 y^{2} + 6 x + 10 y + 9 = 0

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - (- \frac{5}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, - \frac{5}{2}), r = 2

x^{2} + y^{2} + 4 x - 2 y = 4

x^{2} + y^{2} + 40 x + 20 y + 200 = 0

(x - 3)^{2} + (y - 2)^{2} = 5^{2}

x^{2} + y^{2} - x + y + \frac{1}{4} = 0

x^{2} + (- y)^{2} = 9

What is 2x^2+2y^2+6x+10y+9=0 ?
The solution to 2x^2+2y^2+6x+10y+9=0 is Circle with (a,b)=(-3/2 ,-5/2),r=2