What is 2x^2+8x+2y^2-6y=18 ?

The solution to 2x^2+8x+2y^2-6y=18 is Circle with (a,b)=(-2, 3/2),r=(sqrt(61))/2

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2x^2+8x+2y^2-6y=18

2 x^{2} + 8 x + 2 y^{2} - 6 y = 18

(a, b) = (- 2, \frac{3}{2}), r = \frac{61}{2}

Solution steps

2 x^{2} + 8 x + 2 y^{2} - 6 y = 18

Rewrite

2 x^{2} + 8 x + 2 y^{2} - 6 y = 18

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{3}{2})^{2} = (\frac{61}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{3}{2}), r = \frac{61}{2}

x^{2} - 110 + y^{2} = 1

x^{2} + y^{2} + 3 x - y - 1 = 0

x^{2} + y^{2} - 4 x + 2 y = 4

x^{2} + y^{2} - 4 x + 2 y = 0

x^{2} + y^{2} - \frac{20}{17} x - \frac{72}{17} y - \frac{912}{17} = 0

What is 2x^2+8x+2y^2-6y=18 ?
The solution to 2x^2+8x+2y^2-6y=18 is Circle with (a,b)=(-2, 3/2),r=(sqrt(61))/2