What is y3.6^2=(x+0.001)^2+(y+0.3)^2 ?

The solution to y3.6^2=(x+0.001)^2+(y+0.3)^2 is Circle with (a,b)=(-0.001,6.18),r=6.17271…

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y3.6^2=(x+0.001)^2+(y+0.3)^2

y 3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

(a, b) = (- 0.001, 6.18), r = 6.17271 \dots

Solution steps

y \cdot 3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

Rewrite

y 3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

in the form of the standard circle equation

(x - (- 0.001))^{2} + (y - 6.18)^{2} = 6.17271 \dots^{2}

Therefore the circle properties are:

(a, b) = (- 0.001, 6.18), r = 6.17271 \dots

3 x^{2} - 15 x = - 3 y^{2}

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y^{2} - 26 x + 25 y + 5 = - x^{2}

What is y3.6^2=(x+0.001)^2+(y+0.3)^2 ?
The solution to y3.6^2=(x+0.001)^2+(y+0.3)^2 is Circle with (a,b)=(-0.001,6.18),r=6.17271…