What is x^2+y^2+4x-10=0 ?

The solution to x^2+y^2+4x-10=0 is Circle with (a,b)=(-2,0),r=sqrt(14)

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x^2+y^2+4x-10=0

x^{2} + y^{2} + 4 x - 10 = 0

(a, b) = (- 2, 0), r = 14

Solution steps

x^{2} + y^{2} + 4 x - 10 = 0

Rewrite

x^{2} + y^{2} + 4 x - 10 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 0)^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 14

x^{2} + y^{2} - 4 x + 12 y - 20 = 0

x^{2} + y^{2} + 10 x - 6 y + 9 = 0

(x - 0)^{(2)} + (y - 0)^{(2)} = 3 2^{2}

y^{2} = 5 0^{2} - x^{2}

x^{2} + y^{2} - 2 x + 6 y + 5 = 0

What is x^2+y^2+4x-10=0 ?
The solution to x^2+y^2+4x-10=0 is Circle with (a,b)=(-2,0),r=sqrt(14)