What is (y-1)^2+(x-5)^2=1 ?

The solution to (y-1)^2+(x-5)^2=1 is Circle with (a,b)=(5,1),r=1

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(y-1)^2+(x-5)^2=1

(y - 1)^{2} + (x - 5)^{2} = 1

(a, b) = (5, 1), r = 1

Solution steps

(y - 1)^{2} + (x - 5)^{2} = 1

Rewrite

(y - 1)^{2} + (x - 5)^{2} = 1

in the form of the standard circle equation

(x - 5)^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (5, 1), r = 1

x^{(2)} + y^{(2)} - 3 x + 5 y - 14 = 0

x^{2} + y^{2} + 10 y + 9 = 0

(x - 15)^{2} + y^{2} = 25

(x + 1)^{2} + (y - 3)^{2} = 49

(x + 1)^{2} + (y - 3)^{2} = 36

What is (y-1)^2+(x-5)^2=1 ?
The solution to (y-1)^2+(x-5)^2=1 is Circle with (a,b)=(5,1),r=1