What is (y-0)^2+(x-0)^2=49 ?

The solution to (y-0)^2+(x-0)^2=49 is Circle with (a,b)=(0,0),r=7

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(y-0)^2+(x-0)^2=49

(y - 0)^{2} + (x - 0)^{2} = 49

(a, b) = (0, 0), r = 7

Solution steps

(y - 0)^{2} + (x - 0)^{2} = 49

Rewrite

(y - 0)^{2} + (x - 0)^{2} = 49

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 7

x^{2} + y^{2} + 2 x - 8 y - 13 = 0

x^{2} - 2 x + y^{2} + 6 y = - 6

x^{2} + 18 x + y^{2} + 4 y + 81 = 0

x^{2} + 6 x + y^{2} - 8 y = - 16

40 (y - 5)^{2} + 40 (x + 2)^{2} = 2000

What is (y-0)^2+(x-0)^2=49 ?
The solution to (y-0)^2+(x-0)^2=49 is Circle with (a,b)=(0,0),r=7