What is 5x^2+5y^2-3x=0 ?

The solution to 5x^2+5y^2-3x=0 is Circle with (a,b)=(3/10 ,0),r= 3/10

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5x^2+5y^2-3x=0

5 x^{2} + 5 y^{2} - 3 x = 0

(a, b) = (\frac{3}{10}, 0), r = \frac{3}{10}

Solution steps

5 x^{2} + 5 y^{2} - 3 x = 0

Rewrite

5 x^{2} + 5 y^{2} - 3 x = 0

in the form of the standard circle equation

(x - \frac{3}{10})^{2} + (y - 0)^{2} = (\frac{3}{10})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{10}, 0), r = \frac{3}{10}

x^{2} + y^{2} + 4 y - 21 = 0

(x - 4)^{2} + (y - 0)^{2} = 16

y^{2} = (7 + x) (7 - x)

x^{2} + y^{2} - 4 x - 4 y - 8 = 0

y^{(2)} + 4 x - 3 + x^{(2)} + 6 y = 0

What is 5x^2+5y^2-3x=0 ?
The solution to 5x^2+5y^2-3x=0 is Circle with (a,b)=(3/10 ,0),r= 3/10