What is 2x^2+12x+18-y^2=3(2-y^2) ?

The solution to 2x^2+12x+18-y^2=3(2-y^2) is Circle with (a,b)=(-3,0),r=sqrt(3)

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2x^2+12x+18-y^2=3(2-y^2)

2 x^{2} + 12 x + 18 - y^{2} = 3 (2 - y^{2})

(a, b) = (- 3, 0), r = 3

Solution steps

2 x^{2} + 12 x + 18 - y^{2} = 3 (2 - y^{2})

Rewrite

2 x^{2} + 12 x + 18 - y^{2} = 3 (2 - y^{2})

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 3

2 x^{2} + 2 y + 2 y^{2} + 8 x + 4 y - 3 = 0

X^{2} + Y^{2} - 4 = 0

64 = a^{2} + b^{2}

x^{2} + y^{2} + 2 x + 6 y + 1 = 0

x^{2} + y^{2} - 6 x - 2 y - 26 = 0

What is 2x^2+12x+18-y^2=3(2-y^2) ?
The solution to 2x^2+12x+18-y^2=3(2-y^2) is Circle with (a,b)=(-3,0),r=sqrt(3)