What is 144x^2+144y^2+192y+72x+37=0 ?

The solution to 144x^2+144y^2+192y+72x+37=0 is Circle with (a,b)=(-1/4 ,-2/3),r= 1/2

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144x^2+144y^2+192y+72x+37=0

144 x^{2} + 144 y^{2} + 192 y + 72 x + 37 = 0

(a, b) = (- \frac{1}{4}, - \frac{2}{3}), r = \frac{1}{2}

Solution steps

144 x^{2} + 144 y^{2} + 192 y + 72 x + 37 = 0

Rewrite

144 x^{2} + 144 y^{2} + 192 y + 72 x + 37 = 0

in the form of the standard circle equation

(x - (- \frac{1}{4}))^{2} + (y - (- \frac{2}{3}))^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{4}, - \frac{2}{3}), r = \frac{1}{2}

(x - 6)^{2} + (y + 5)^{2} = 25

(x - 5)^{2} + (y + 1)^{2} = 25

4 x^{2} + 4 y^{2} + 48 y + 143 = 0

x^{2} + y^{2} = 2 π

x^{2} + y^{2} - 4 x - 6 y + 12 = 0

What is 144x^2+144y^2+192y+72x+37=0 ?
The solution to 144x^2+144y^2+192y+72x+37=0 is Circle with (a,b)=(-1/4 ,-2/3),r= 1/2