What is (x-10)^2+(y-2)^2=26 ?

The solution to (x-10)^2+(y-2)^2=26 is Circle with (a,b)=(10,2),r=sqrt(26)

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(x-10)^2+(y-2)^2=26

(x - 10)^{2} + (y - 2)^{2} = 26

(a, b) = (10, 2), r = 26

Solution steps

(x - 10)^{2} + (y - 2)^{2} = 26

Rewrite

(x - 10)^{2} + (y - 2)^{2} = 26

in the form of the standard circle equation

(x - 10)^{2} + (y - 2)^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (10, 2), r = 26

x^{2} - 8 x + y^{2} - 4 y = 29

(x + 11)^{2} + (y + 6)^{2} = 324

(x + 3)^{2} + (y - 2)^{2} = 1^{2}

(x - 1)^{2} + (y)^{2} = 1

x^{2} - 8 x + y^{2} + 12 y = - 43

What is (x-10)^2+(y-2)^2=26 ?
The solution to (x-10)^2+(y-2)^2=26 is Circle with (a,b)=(10,2),r=sqrt(26)