What is x^2+2x+1+y^2-8y+16=-16+1+16 ?

The solution to x^2+2x+1+y^2-8y+16=-16+1+16 is Circle with (a,b)=(-1,4),r=1

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x^2+2x+1+y^2-8y+16=-16+1+16

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

(a, b) = (- 1, 4), r = 1

Solution steps

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

Rewrite

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 4)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (- 1, 4), r = 1

3 x^{2} + 3 y^{2} - 3 x - 3 y - 9 = 0

(x - 6)^{2} + (y + 2)^{2} = 16

x^{2} - 8 x + 16 + y^{2} - 4 y + 4 = (34)^{2}

(x - 3)^{2} + (y - 4)^{2} = (2)^{2}

3 x^{2} + 3 y^{2} - 6 x - y + 1 = 0

What is x^2+2x+1+y^2-8y+16=-16+1+16 ?
The solution to x^2+2x+1+y^2-8y+16=-16+1+16 is Circle with (a,b)=(-1,4),r=1