What is 25x^2+25y^2-20x+60y-360=0 ?

The solution to 25x^2+25y^2-20x+60y-360=0 is Circle with (a,b)=(2/5 ,-6/5),r=4

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25x^2+25y^2-20x+60y-360=0

25 x^{2} + 25 y^{2} - 20 x + 60 y - 360 = 0

(a, b) = (\frac{2}{5}, - \frac{6}{5}), r = 4

Solution steps

25 x^{2} + 25 y^{2} - 20 x + 60 y - 360 = 0

Rewrite

25 x^{2} + 25 y^{2} - 20 x + 60 y - 360 = 0

in the form of the standard circle equation

(x - \frac{2}{5})^{2} + (y - (- \frac{6}{5}))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{5}, - \frac{6}{5}), r = 4

x^{2} + y^{2} - 4 x + 4 y = 4

x^{2} + y^{2} - 16 x + 12 y + 48 = 0

x^{2} = 3 - y^{2}

x^{2} + y^{2} = 1999

x^{2} + y^{2} - 7 x = 36 - 4 y

What is 25x^2+25y^2-20x+60y-360=0 ?
The solution to 25x^2+25y^2-20x+60y-360=0 is Circle with (a,b)=(2/5 ,-6/5),r=4