What is (x+9/4)^2+(y+4)^2=36 ?

The solution to (x+9/4)^2+(y+4)^2=36 is Circle with (a,b)=(-9/4 ,-4),r=6

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(x+9/4)^2+(y+4)^2=36

(x + \frac{9}{4})^{2} + (y + 4)^{2} = 36

(a, b) = (- \frac{9}{4}, - 4), r = 6

Solution steps

(x + \frac{9}{4})^{2} + (y + 4)^{2} = 36

Rewrite

(x + \frac{9}{4})^{2} + (y + 4)^{2} = 36

in the form of the standard circle equation

(x - (- \frac{9}{4}))^{2} + (y - (- 4))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{4}, - 4), r = 6

x^{2} + y^{2} + 6 x - 8 y - 11 = 0

x^{2} + y^{2} - 8 x + 10 y - 88 = 0

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 1

4 x^{2} + 4 y^{2} + 8 y - 45 = 0

x, h (x)^{2} + (8 - x)^{2} = 49

What is (x+9/4)^2+(y+4)^2=36 ?
The solution to (x+9/4)^2+(y+4)^2=36 is Circle with (a,b)=(-9/4 ,-4),r=6