What is (x-6)^2+(y-10)^2=(sqrt(5))^2 ?

The solution to (x-6)^2+(y-10)^2=(sqrt(5))^2 is Circle with (a,b)=(6,10),r=sqrt((\sqrt{5))^2}

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(x-6)^2+(y-10)^2=(sqrt(5))^2

(x - 6)^{2} + (y - 10)^{2} = (5)^{2}

(a, b) = (6, 10), r = (5)^{2}

Solution steps

(x - 6)^{2} + (y - 10)^{2} = (5)^{2}

Rewrite

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - 10)^{2} = ((5)^{2})^{2}

Therefore the circle properties are:

(a, b) = (6, 10), r = (5)^{2}

(x + 6)^{2} + (y + 8)^{2} = 100

3 x^{2} + 3 y^{2} - 12 x - 24 y + 12 = 0

(x - 5)^{2} + (y - 7)^{2} = 4

x^{2} + y^{2} - 4 x + 12 y - 9 = 0

x^{2} + y^{2} = 3 - y

What is (x-6)^2+(y-10)^2=(sqrt(5))^2 ?
The solution to (x-6)^2+(y-10)^2=(sqrt(5))^2 is Circle with (a,b)=(6,10),r=sqrt((\sqrt{5))^2}