What is (x+18.5)^2+(y-3.1)^2=71 ?

The solution to (x+18.5)^2+(y-3.1)^2=71 is Circle with (a,b)=(-18.5,3.1),r=sqrt(71)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+18.5)^2+(y-3.1)^2=71

(x + 18.5)^{2} + (y - 3.1)^{2} = 71

(a, b) = (- 18.5, 3.1), r = 71

Solution steps

(x + 18.5)^{2} + (y - 3.1)^{2} = 71

Rewrite

(x + 18.5)^{2} + (y - 3.1)^{2} = 71

in the form of the standard circle equation

(x - (- 18.5))^{2} + (y - 3.1)^{2} = (71)^{2}

Therefore the circle properties are:

(a, b) = (- 18.5, 3.1), r = 71

(x + 2)^{2} + (y + 2)^{2} = 3

(x + 3) (x + 3) + (y + 2) (y + 2) = 16

(x + 1)^{2} + y^{2} = \frac{4}{9}

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

x^{2} + y^{2} + 10 y + 19 = 0

What is (x+18.5)^2+(y-3.1)^2=71 ?
The solution to (x+18.5)^2+(y-3.1)^2=71 is Circle with (a,b)=(-18.5,3.1),r=sqrt(71)