What is X^2+Y^2+6X-8Y=11 ?

The solution to X^2+Y^2+6X-8Y=11 is Circle with (a,b)=(-3,4),r=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

X^2+Y^2+6X-8Y=11

X^{2} + Y^{2} + 6 X - 8 Y = 11

(a, b) = (- 3, 4), r = 6

Solution steps

X^{2} + Y^{2} + 6 X - 8 Y = 11

Rewrite

X^{2} + Y^{2} + 6 X - 8 Y = 11

in the form of the standard circle equation

(X - (- 3))^{2} + (Y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 6

x^{2} + y^{2} + 2 x - 6 y + 9 = 0

4 x^{2} + 36 x + 4 y^{2} - 24 y + 36 = 0

(x + 3)^{2} + (y + 5)^{2} = 28

x^{2} + (y - 2)^{2} = 5

4 (x - 4)^{2} + 4 y^{2} = 36

What is X^2+Y^2+6X-8Y=11 ?
The solution to X^2+Y^2+6X-8Y=11 is Circle with (a,b)=(-3,4),r=6