What is (x+7)^2+(y-2)^2=81 ?

The solution to (x+7)^2+(y-2)^2=81 is Circle with (a,b)=(-7,2),r=9

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(x+7)^2+(y-2)^2=81

(x + 7)^{2} + (y - 2)^{2} = 81

(a, b) = (- 7, 2), r = 9

Solution steps

(x + 7)^{2} + (y - 2)^{2} = 81

Rewrite

(x + 7)^{2} + (y - 2)^{2} = 81

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 2)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 7, 2), r = 9

(x - 12)^{2} + (y + 16)^{2} = 400

(x + 7)^{2} + (y - 2)^{2} = 64

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{4} = 1

x^{2} - 4 y + y^{2} - 21 = 0

(x - 2)^{(2)} + (y - 3)^{(2)} = 2^{(2)}

What is (x+7)^2+(y-2)^2=81 ?
The solution to (x+7)^2+(y-2)^2=81 is Circle with (a,b)=(-7,2),r=9