What is x^{(2)}+y^{(2)}-6x-8y-3=0 ?

The solution to x^{(2)}+y^{(2)}-6x-8y-3=0 is Circle with (a,b)=(3,4),r=2sqrt(7)

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x^{(2)}+y^{(2)}-6x-8y-3=0

x^{(2)} + y^{(2)} - 6 x - 8 y - 3 = 0

(a, b) = (3, 4), r = 27

Solution steps

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

Rewrite

x^{2} + y^{2} - 6 x - 8 y - 3 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = (27)^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 27

- 2 x^{2} - 36 x - 2 y^{2} - 122 = 0

x^{2} + y^{2} - x + 6 y = 1

(x + 4)^{2} + (y - 7)^{2} = 25

x^{2} + y^{2} + 4 x - 2 y + 1 > 0

(x + 8)^{2} + (y - 4)^{2} = 20

What is x^{(2)}+y^{(2)}-6x-8y-3=0 ?
The solution to x^{(2)}+y^{(2)}-6x-8y-3=0 is Circle with (a,b)=(3,4),r=2sqrt(7)