What is (x^2-10x+25)+(y^2+4y+4)=36 ?

The solution to (x^2-10x+25)+(y^2+4y+4)=36 is Circle with (a,b)=(5,-2),r=6

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(x^2-10x+25)+(y^2+4y+4)=36

(x^{2} - 10 x + 25) + (y^{2} + 4 y + 4) = 36

(a, b) = (5, - 2), r = 6

Solution steps

x^{2} - 10 x + 25 + (y^{2} + 4 y + 4) = 36

Rewrite

x^{2} - 10 x + 25 + (y^{2} + 4 y + 4) = 36

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 6

x^{2} + y^{2} - 2 x - 2 y = 2

x^{2} + y^{2} - 6 x + 12 y + 41 = 0

(\frac{x - 19}{4})^{2} + (\frac{y - 9}{4})^{2} = 17

x^{2} + y^{2} + 4 x - 8 y + 16 = 0

2 x^{2} + 4 x + 2 y^{2} = 0

What is (x^2-10x+25)+(y^2+4y+4)=36 ?
The solution to (x^2-10x+25)+(y^2+4y+4)=36 is Circle with (a,b)=(5,-2),r=6