What is (x-(-4))^2+(y-3)^2=sqrt(7) ?

The solution to (x-(-4))^2+(y-3)^2=sqrt(7) is Circle with (a,b)=(-4,3),r=sqrt(\sqrt{7)}

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(x-(-4))^2+(y-3)^2=sqrt(7)

(x - (- 4))^{2} + (y - 3)^{2} = 7

(a, b) = (- 4, 3), r = 7

Solution steps

(x - (- 4))^{2} + (y - 3)^{2} = 7

Rewrite

(x - (- 4))^{2} + (y - 3)^{2} = 7

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 3)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 3), r = 7

x^{2} + y^{2} - 16 x = 49

x^{2} + y^{2} + 12 x - 10 y + 45 = 0

(x + 5)^{2} + (y - 2)^{2} = 2

x^{2} + y^{2} + 10 x - 10 y + 25 = 0

(x - 2)^{2} + (y - 5)^{2} = 13

What is (x-(-4))^2+(y-3)^2=sqrt(7) ?
The solution to (x-(-4))^2+(y-3)^2=sqrt(7) is Circle with (a,b)=(-4,3),r=sqrt(\sqrt{7)}