What is (x-1)^2+y^2=6 ?

The solution to (x-1)^2+y^2=6 is Circle with (a,b)=(1,0),r=sqrt(6)

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(x-1)^2+y^2=6

(x - 1)^{2} + y^{2} = 6

(a, b) = (1, 0), r = 6

Solution steps

(x - 1)^{2} + y^{2} = 6

Rewrite

(x - 1)^{2} + y^{2} = 6

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 6

2 x - 4 y - x^{2} - y^{2} - 1 \geq 0

(x - (- 15))^{2} + (y - 37)^{2} = 2^{2}

(x + 1)^{2} + (y + 3)^{2} = 25

(x - 2)^{2} + (y + 5)^{2} = 100

(x + 3.2625400000000 \dots)^{2} + (y + 8)^{2} = + 1936

What is (x-1)^2+y^2=6 ?
The solution to (x-1)^2+y^2=6 is Circle with (a,b)=(1,0),r=sqrt(6)