What is (x-(-7))^2+(y-(-6))^2=sqrt(19)^2 ?

The solution to (x-(-7))^2+(y-(-6))^2=sqrt(19)^2 is Circle with (a,b)=(-7,-6),r=sqrt((\sqrt{19))^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-(-7))^2+(y-(-6))^2=sqrt(19)^2

(x - (- 7))^{2} + (y - (- 6))^{2} = 19^{2}

(a, b) = (- 7, - 6), r = (19)^{2}

Solution steps

(x - (- 7))^{2} + (y - (- 6))^{2} = (19)^{2}

Rewrite

(x - (- 7))^{2} + (y - (- 6))^{2} = 19^{2}

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 6))^{2} = ((19)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 6), r = (19)^{2}

x^{2} + y^{2} - 8 x + 2 y + 4 = 0

(x - 2)^{2} + (y + 1)^{2} = 13

(x - \frac{7}{2})^{2} + (y - 1)^{2} = 4.27

x^{2} + 7 x + y^{2} - 8 y = 3

x^{2} + y^{2} + 10 x - 14 y - 70 = 0

What is (x-(-7))^2+(y-(-6))^2=sqrt(19)^2 ?
The solution to (x-(-7))^2+(y-(-6))^2=sqrt(19)^2 is Circle with (a,b)=(-7,-6),r=sqrt((\sqrt{19))^2}