What is 2x^2+2y^2=12y-10 ?

The solution to 2x^2+2y^2=12y-10 is Circle with (a,b)=(0,3),r=2

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2x^2+2y^2=12y-10

2 x^{2} + 2 y^{2} = 12 y - 10

(a, b) = (0, 3), r = 2

Solution steps

2 x^{2} + 2 y^{2} = 12 y - 10

Rewrite

2 x^{2} + 2 y^{2} = 12 y - 10

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 2

x^{2} + y^{2} + 8 x - 6 y + 8 = 0

x^{2} + (y - 9)^{2} = 8

2 x^{2} + 2 y^{2} + 28 y - 8 y + 4 = 0

x^{2} + (y - 9)^{2} = 1

x^{2} + y^{2} + 5 x + 4 y - 34 = 0

What is 2x^2+2y^2=12y-10 ?
The solution to 2x^2+2y^2=12y-10 is Circle with (a,b)=(0,3),r=2