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Popular >

foci y^2=8x

Solution

foci

y^{2} = 8 x

Solution

(2, 0)

Solution steps

Rewrite

y^{2} = 8 x

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + 2, 0)

Refine

(2, 0)

Popular Examples

vertices f(x)=-x^2+4x+5 vertices

f (x) = - x^{2} + 4 x + 5

100x^2+100y^2-100x+400y+409=0

100 x^{2} + 100 y^{2} - 100 x + 400 y + 409 = 0

y^{2} = 28 x

9 x^{2} + 4 y^{2} = 1

radius x^2+y^2=64 radius

x^{2} + y^{2} = 64

Frequently Asked Questions (FAQ)

What is the foci y^2=8x ?
The foci y^2=8x is (2,0)