What is (x+y)^{(2)}=x2+2xy+y2 ?

The solution to (x+y)^{(2)}=x2+2xy+y2 is Circle with (a,b)=(1,1),r=sqrt(2)

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(x+y)^{(2)}=x2+2xy+y2

(x + y)^{(2)} = x 2 + 2 x y + y 2

(a, b) = (1, 1), r = 2

Solution steps

(x + y)^{2} = x \cdot 2 + 2 x y + y \cdot 2

Rewrite

(x + y)^{2} = x 2 + 2 x y + y 2

in the form of the standard circle equation

(x - 1)^{2} + (y - 1)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 1), r = 2

x^{2} + y^{2} = 25 (0, - 5)

x^{2} = - y^{2} + 9

x^{2} = - y^{2} + 8

x^{2} + y^{2} + 14 x - 2 y = - 1

x^{2} = - y^{2} + 1

What is (x+y)^{(2)}=x2+2xy+y2 ?
The solution to (x+y)^{(2)}=x2+2xy+y2 is Circle with (a,b)=(1,1),r=sqrt(2)