What is x^2+y^2-6x+1=0 ?

The solution to x^2+y^2-6x+1=0 is Circle with (a,b)=(3,0),r=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-6x+1=0

x^{2} + y^{2} - 6 x + 1 = 0

(a, b) = (3, 0), r = 22

Solution steps

x^{2} + y^{2} - 6 x + 1 = 0

Rewrite

x^{2} + y^{2} - 6 x + 1 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = (22)^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 22

4 x^{2} + 4 y^{2} - 8 x + 16 y + 4 = 0

\frac{( x - 5 ) ^{2}}{2} + \frac{( y + 3 ) ^{2}}{2} = 1

x^{2} + y^{2} + 2 (\frac{29}{22}) x + 2 (\frac{29}{22}) y + (- \frac{142}{11}) = 0

(x - 7)^{2} + (y + 3)^{2} - 81 = 0

3 x^{2} + 3 y^{2} = 9

What is x^2+y^2-6x+1=0 ?
The solution to x^2+y^2-6x+1=0 is Circle with (a,b)=(3,0),r=2sqrt(2)