What is (x-(-4))^2+(y-(9))^2=3^2 ?

The solution to (x-(-4))^2+(y-(9))^2=3^2 is Circle with (a,b)=(-4,9),r=3

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(x-(-4))^2+(y-(9))^2=3^2

(x - (- 4))^{2} + (y - (9))^{2} = 3^{2}

(a, b) = (- 4, 9), r = 3

Solution steps

(x - (- 4))^{2} + (y - 9)^{2} = 3^{2}

Rewrite

(x - (- 4))^{2} + (y - 9)^{2} = 3^{2}

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 9)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, 9), r = 3

x^{2} + (y + 4)^{2} = 25

(x^{2} + 2 x + 1) + (y^{2} - 6 y + 9) = - 7 + 1 + 9

4 x^{(2)} + 40 x + 4 y^{(2)} - 32 y = 5

x^{2} + y^{2} - 10 x + 2 y + 20 = 0

(X + 8)^{2} + (Y + 6)^{2} = 100

What is (x-(-4))^2+(y-(9))^2=3^2 ?
The solution to (x-(-4))^2+(y-(9))^2=3^2 is Circle with (a,b)=(-4,9),r=3