What is (x+9)^2+(y+2)^2=4 ?

The solution to (x+9)^2+(y+2)^2=4 is Circle with (a,b)=(-9,-2),r=2

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(x+9)^2+(y+2)^2=4

(x + 9)^{2} + (y + 2)^{2} = 4

(a, b) = (- 9, - 2), r = 2

Solution steps

(x + 9)^{2} + (y + 2)^{2} = 4

Rewrite

(x + 9)^{2} + (y + 2)^{2} = 4

in the form of the standard circle equation

(x - (- 9))^{2} + (y - (- 2))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 9, - 2), r = 2

x^{2} + y^{2} + 6 x - 4 y - 36 = 0

(x + 2)^{2} + (y - 3)^{2} = 4^{2}

x^{(2)} + y^{(2)} + 2 x + 4 y - 15 = 0

(x - 3)^{2} + (y - 5)^{2} = 306.25

x^{2} + y^{2} - 8 x + 2 y + 10 = 0

What is (x+9)^2+(y+2)^2=4 ?
The solution to (x+9)^2+(y+2)^2=4 is Circle with (a,b)=(-9,-2),r=2