What is (x)^2+(y-4)^2=73 ?

The solution to (x)^2+(y-4)^2=73 is Circle with (a,b)=(0,4),r=sqrt(73)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x)^2+(y-4)^2=73

(x)^{2} + (y - 4)^{2} = 73

(a, b) = (0, 4), r = 73

Solution steps

x^{2} + (y - 4)^{2} = 73

Rewrite

x^{2} + (y - 4)^{2} = 73

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = (73)^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 73

x^{2} + y^{2} - x - y - \frac{1}{2} = 0

(x - 5)^{2} + (y + 4)^{2} = 100

x^{2} + y^{2} \leq \frac{3}{4}

x^{2} - 8 x + 16 + y^{2} + 2 y + 1 = 4

x^{2} + y^{2} + 3 x - 10 y - 5 = 0

What is (x)^2+(y-4)^2=73 ?
The solution to (x)^2+(y-4)^2=73 is Circle with (a,b)=(0,4),r=sqrt(73)