What is 4=(6-x)^2+(2-y)^2 ?

The solution to 4=(6-x)^2+(2-y)^2 is Circle with (a,b)=(6,2),r=2

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4=(6-x)^2+(2-y)^2

4 = (6 - x)^{2} + (2 - y)^{2}

(a, b) = (6, 2), r = 2

Solution steps

4 = (6 - x)^{2} + (2 - y)^{2}

Rewrite

4 = (6 - x)^{2} + (2 - y)^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - 2)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (6, 2), r = 2

9 x^{2} + 9 y^{2} = 3

x (x + 5) + (y + 2)^{2} = 0

x^{2} + y^{2} - 2 x + 6 y - 111 = 0

36 y^{2} + 36 z^{2} = 9

(x - 2)^{2} + (y - 1)^{2} = 81

What is 4=(6-x)^2+(2-y)^2 ?
The solution to 4=(6-x)^2+(2-y)^2 is Circle with (a,b)=(6,2),r=2