What is 4(x-1)^2+4y^2=9 ?

The solution to 4(x-1)^2+4y^2=9 is Circle with (a,b)=(1,0),r= 3/2

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4(x-1)^2+4y^2=9

4 (x - 1)^{2} + 4 y^{2} = 9

(a, b) = (1, 0), r = \frac{3}{2}

Solution steps

4 (x - 1)^{2} + 4 y^{2} = 9

Rewrite

4 (x - 1)^{2} + 4 y^{2} = 9

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = \frac{3}{2}

x^{2} + 8 x + 16 + y^{2} + 4 y + 4 = 4

(x - 2)^{2} + (y + 4)^{2} = 3

(x + 8)^{2} + y^{2} = 1

x^{2} + y^{2} - 10 x + 10 y = 81

x^{2} + y^{2} \geq 36

What is 4(x-1)^2+4y^2=9 ?
The solution to 4(x-1)^2+4y^2=9 is Circle with (a,b)=(1,0),r= 3/2