What is (x-3)^2+(y+8)^2=65 ?

The solution to (x-3)^2+(y+8)^2=65 is Circle with (a,b)=(3,-8),r=sqrt(65)

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(x-3)^2+(y+8)^2=65

(x - 3)^{2} + (y + 8)^{2} = 65

(a, b) = (3, - 8), r = 65

Solution steps

(x - 3)^{2} + (y + 8)^{2} = 65

Rewrite

(x - 3)^{2} + (y + 8)^{2} = 65

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 8))^{2} = (65)^{2}

Therefore the circle properties are:

(a, b) = (3, - 8), r = 65

(x - 4)^{2} + (y + 10)^{2} = 81

x^{2} + y^{2} + 14 x - 10 y + 65 = 0 x

3 x^{2} + 3 y^{2} - 30 x - 6 y + 75 = 0

0.2 x^{2} + x + 0.2 y^{2} - 4 y = 1

x^{2} + y^{2} - 5 x = 20 - 2 y

What is (x-3)^2+(y+8)^2=65 ?
The solution to (x-3)^2+(y+8)^2=65 is Circle with (a,b)=(3,-8),r=sqrt(65)