What is x^2+y^2+12x+2y+1/16 =0 ?

The solution to x^2+y^2+12x+2y+1/16 =0 is Circle with (a,b)=(-6,-1),r=(sqrt(591))/4

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x^2+y^2+12x+2y+1/16 =0

x^{2} + y^{2} + 12 x + 2 y + \frac{1}{16} = 0

(a, b) = (- 6, - 1), r = \frac{591}{4}

Solution steps

x^{2} + y^{2} + 12 x + 2 y + \frac{1}{16} = 0

Rewrite

x^{2} + y^{2} + 12 x + 2 y + \frac{1}{16} = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - (- 1))^{2} = (\frac{591}{4})^{2}

Therefore the circle properties are:

(a, b) = (- 6, - 1), r = \frac{591}{4}

(x - 3)^{2} + (y + 2)^{2} = 17

x^{2} + y^{2} - 12 x = - 4 y + 5

(3 x - 2 - 2)^{(2)} + (3 y + 1)^{(2)} = 9

x^{2} + y^{2} - 8 x + 6 y = - 24

x^{2} + y^{2} - 16 x + 8 y + 64 = 0

What is x^2+y^2+12x+2y+1/16 =0 ?
The solution to x^2+y^2+12x+2y+1/16 =0 is Circle with (a,b)=(-6,-1),r=(sqrt(591))/4