What is (x-2)^{(2)}+(y-3)^{(2)}=7 ?

The solution to (x-2)^{(2)}+(y-3)^{(2)}=7 is Circle with (a,b)=(2,3),r=sqrt(7)

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(x-2)^{(2)}+(y-3)^{(2)}=7

(x - 2)^{(2)} + (y - 3)^{(2)} = 7

(a, b) = (2, 3), r = 7

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 7

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 7

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 7

(a + b) + (a - b) = a^{2} + b^{2}

(x + 3)^{2} + (y + 2)^{2} = 36

x^{2} + y^{2} + 10 x - 12 y + 12 = 0

- y^{2} = (x + 2) (x - 3)

x^{2} - 4 x + y^{2} - 10 y = 35

What is (x-2)^{(2)}+(y-3)^{(2)}=7 ?
The solution to (x-2)^{(2)}+(y-3)^{(2)}=7 is Circle with (a,b)=(2,3),r=sqrt(7)