What is (x+2)^{(2)}+(y+5)^{(2)}=144 ?

The solution to (x+2)^{(2)}+(y+5)^{(2)}=144 is Circle with (a,b)=(-2,-5),r=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+2)^{(2)}+(y+5)^{(2)}=144

(x + 2)^{(2)} + (y + 5)^{(2)} = 144

(a, b) = (- 2, - 5), r = 12

Solution steps

(x + 2)^{2} + (y + 5)^{2} = 144

Rewrite

(x + 2)^{2} + (y + 5)^{2} = 144

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 5))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 5), r = 12

x^{2} + 4 x + 2^{2} + y^{2} + 8 y + 4^{2} - 5 = 20

x^{2} + y^{2} - 5 x - 3 y = 0

9 x^{2} + 72 x + 9 y^{2} - 12 y + 103 = 0

(x + 3)^{2} + (y - 2)^{2} = 64

x^{2} + y^{2} - 2 x - 2 = 0

What is (x+2)^{(2)}+(y+5)^{(2)}=144 ?
The solution to (x+2)^{(2)}+(y+5)^{(2)}=144 is Circle with (a,b)=(-2,-5),r=12