What is x^2+4x+y^2-y= 3/5 ?

The solution to x^2+4x+y^2-y= 3/5 is Circle with (a,b)=(-2, 1/2),r=(sqrt(97))/(2sqrt(5))

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x^2+4x+y^2-y= 3/5

x^{2} + 4 x + y^{2} - y = \frac{3}{5}

(a, b) = (- 2, \frac{1}{2}), r = \frac{97}{2 5}

Solution steps

x^{2} + 4 x + y^{2} - y = \frac{3}{5}

Rewrite

x^{2} + 4 x + y^{2} - y = \frac{3}{5}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{1}{2})^{2} = (\frac{97}{2 5})^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{1}{2}), r = \frac{97}{2 5}

x^{(2)} + y^{(2)} + 4 x - 2 y + 1 = 0

(x^{2} - 4 x) + (y^{2} + 8 y) = 16

x^{2} + y^{2} - 6 x + 10 y + 27 = 0

x^{2} + y^{2} - 12 x - 12 y + 36 = 0

(x + 3)^{2} + (y - 2)^{2} = 36

What is x^2+4x+y^2-y= 3/5 ?
The solution to x^2+4x+y^2-y= 3/5 is Circle with (a,b)=(-2, 1/2),r=(sqrt(97))/(2sqrt(5))